Let’s compute resistances per unit length:
Have your own tricky heat transfer problem? Drop it in the comments below.
[ Q = 5.67 \times 10^{-8} \cdot 5.44 \times 10^{10} = 5.67 \times 544 = 3084 , \text{W} ] heat transfer example problems
[ R_{total} = 0.03183 + 0.00193 + 0.2653 = 0.2991 , \text{m·K/W} ]
First, compute the thermal resistances per unit area: [ R_A = \frac{0.2}{1.2} = 0.1667 , \text{m²·K/W} ] [ R_B = \frac{0.1}{0.15} = 0.6667 , \text{m²·K/W} ] [ R_{total} = 0.1667 + 0.6667 = 0.8334 , \text{m²·K/W} ] Let’s compute resistances per unit length: Have your
Now heat flux: [ q = \frac{1100 - 50}{0.8334} = \frac{1050}{0.8334} \approx 1260 , \text{W/m}^2 ]
[ R_{cond} = \frac{\ln(0.06/0.05)}{2\pi \cdot 15} = \frac{\ln(1.2)}{94.2478} = \frac{0.1823}{94.2478} = 0.001934 , \text{m·K/W} ] \text{m·K/W} ] First
For black parallel plates, the net radiation is: [ Q = \sigma A (T_1^4 - T_2^4) ] [ Q = 5.67 \times 10^{-8} \cdot 1 \cdot (500^4 - 300^4) ] Compute: ( 500^4 = 6.25 \times 10^{10} ) ( 300^4 = 0.81 \times 10^{10} ) Difference = ( 5.44 \times 10^{10} )