Igcse Chemistry Past Paper 〈VERIFIED 2024〉

From equation: 1 mol Mg → 1 mol H₂ So moles H₂ = 0.10 mol Volume H₂ = 0.10 × 24 = 2.4 dm³ (1 mark for mole ratio, 1 mark for volume)

Exam Board: Cambridge CIE 0620 Paper: 2 – Multiple Choice (Extended) – Extract Topic: Stoichiometry & Mole Calculations Time allowed: 15 minutes (extract) Total marks: 10 Section A: Multiple Choice Questions Question 1 What is the mass of one mole of carbon dioxide (CO₂)? (Ar: C = 12, O = 16) igcse chemistry past paper

What is the number of molecules in 2.0 moles of carbon dioxide? (Avogadro’s constant = 6.02 × 10²³) From equation: 1 mol Mg → 1 mol H₂ So moles H₂ = 0

Calculate the volume occupied by 0.5 moles of oxygen gas (O₂) at room temperature and pressure (RTP). (Molar volume = 24 dm³/mol) (Molar volume = 24 dm³/mol) A) 1

A) 1.20 × 10²³ B) 3.01 × 10²³ C) 6.02 × 10²³ D) 1.20 × 10²⁴ Question 6 Magnesium reacts with hydrochloric acid according to the equation:

Calculate the number of moles of magnesium in 2.4 g of Mg. (Ar: Mg = 24) [2]

A) One mole of any element contains the same number of atoms as one mole of any compound. B) One mole of any gas occupies the same volume at the same temperature and pressure. C) One mole of any substance has the same mass. D) One mole of electrons has a mass of 1 g.